C Program to check the number is palindrome or not

C Program to check the number is palindrome or not

 #include<stdio.h>
#include<conio.h>
void main()
{
int i,temp,sum=0,remainder,number;
clrscr();
printf("Enter the number to check Palindrome: ");
scanf("%d",&number);
temp=number;
while(number>0)
{
remainder=number%10;
number=number/10;
sum=sum*10+remainder;
}
printf("\nreverse of given number is= %d\n",sum);
if(sum==temp)
printf("number is palindrome");
else
printf("number is not palindrome");
getch();
}

C Program to open an existing file and read it

C Program to open an existing file and read it

You have to save the file which you want to read in the home folder (ie in the folder where your c program exists with ). Give the name of file with its extension (like name.txt) when it is asked.

#include <stdlib.h>
#include<stdio.h>
int main()
{
    FILE *fptr;
    char filename[15];
    char ch;
//    clrscr();

    printf("Enter the filename to be opened \n");
    scanf("%s", filename);
    /*  open the file for reading */
    fptr = fopen(filename, "r");
    if (fptr == NULL)
    {
printf("Cannot open file \n");
exit(0);
    }
    ch = fgetc(fptr);
    while (ch != EOF)
    {
printf ("%c", ch);
ch = fgetc(fptr);
    }
    fclose(fptr);
}

C++ Program to count lines,words and characters of a string

C++ Program to count lines,words and characters of a string

#include <iostream>
using namespace std;

class countli
{
    char c;
    int lines,words,chars;
public:
    void input()
    {
       cout<<"Enter string termanate by # : ";
    }
    void operation()
    {
        lines=1;
        words=1;
        chars=1;
        while(c != '#'){
        cin.get(c);
        chars++;
        if(c==' ' || c=='\n')
            words++;
        if(c=='\n')
            lines++;
    }
    }
    void output()
    {
        cout<<"No. of lines"<<lines<<endl;
        cout<<"No. of words"<<words<<endl;
        cout<<"No. of characters"<<chars<<endl;
    }
    };
int main()
{
countli a;
a.input();
a.operation();
a.output();
return 0;
}

C Program to sort n number of integers by using bubble sort technique

C Program to sort n number of integers by using bubble sort technique 

#include<stdio.h>
#include<conio.h>
void swap(int[],int,int);
void dis(int[],int);
void main ()
{
int a[100];
int n,i,temp,j;
clrscr();
printf("Enter how many numbers do you want");
scanf("%d",&n);
printf("Enter the %d numbers",n);
for(i=0;i<n;i++)
{
scanf("%d",&a[i]);
}
printf("Unsorted values\n");
dis(a,n);
for (i=0;i<n;i++)
{
for(j=0;j<n-1;j++)
  {
if(a[i]<a[j])
    {
swap(a,i,j);
    }
    }
}
printf("Sorted values are as follow\n");
dis(a,n);
getch();
}

void dis (int b[],int n)
{
int i;
for(i=0;i<n;i++)
printf("%d\n",b[i]);
}
void swap(int b[],int k,int l)
{
int temp;
temp=b[k];
b[k]=b[l];
b[l]=temp;
}

C Program to create a menu based program using switch case

C Program to create a menu based program using switch case

#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
void main()
{
int s,n1,rem,rev=0,num,n,f=1,i,sum=0;
clrscr();
printf("Choose the option\n");
printf("1. Cheque wheather number is palindrome\t2. Factorial value\n");
printf("3. Sum of n natural number\t\t4. Exit\n");
scanf("%d",&s);
switch(s)
{
case 1:
printf("Enter the number\n");
scanf("%d",&n1);
num=n1;
while (n1>0)
{
rem=n1%10;
n1=n1/10;
rev=rev*10+rem;
}
printf("reverse number is %d\n",rev);
if(num==rev)
printf("Number is palindrome");
else
printf("Number is not palindrome\n");
break;
case 2:
printf("Enter the number\n");
scanf("%d",&n);
for(i=n;i>0;i--)
f=f*i;
printf("factorial is %d",f);
break;
case 3:
printf("How many numbers do you want to enter\n");
scanf("%d",&n);
printf("Enter %d numbers\n",n);
for(i=0;i<n;i++)
{
scanf("%d",&n1);
sum=sum+n1;
}
printf("sum of %d numbers is %d",n,sum);
break;
case 4:
exit();
}
getch(0);
}

C++ Program to swap two integers using friend function

C++ Program to swap two integers using friend function

In object-oriented programming, a friend function that is a "friend" of a given class is allowed access to private and protected data in that class that it would not normally be able to as if the data was public. Normally, a function that is defined outside of a class cannot access such information. Declaring a function a friend of a class allows this, in languages where the concept is supported.
                                                                                         wiki

#include<iostream.h>
class b;
class a
{
int x1;
public:
void reada()
{
cout<<"Enter x1 value\n";
cin>>x1;
}
friend void swap (a &,b &);
};
class b
{
int x2;
public:
void readb()
{
cout<<"Enter an x2 value\n";
cin>>x2;
}
friend void swap (a &,b &);
};
void swap (a &o1, b &o2)
{
int t;
cout<<"Before swapping\nx1="<<o1.x1<<"\n"<<"x2="<<o2.x2<<"\n";
t=o1.x1;
o1.x1=o2.x2;
o2.x2=t;
cout<<"After swapping\nx1="<<o1.x1<<"\n"<<"x2="<<o2.x2<<"\n";
}
void main()
{
clrscr();
a a;
a.reada();
b b;
b.readb();
swap(a,b);
}

C++ Program to find out the sum of digits of a number

C++ Program to find out the sum of digits of a number

#include<iostream.h>
class sumdig
{
int n,rem,rem1;
public:
void input()
{
cout<<"Enter the number\n";
cin>>n;
}
void calculation()
{
rem1=0;
while (n>0)
{
rem=n%10;
n=n/10;
rem1=rem1+rem;
}
}
void output()
{
cout<<"Sum of single digits is "<<rem1;
}
};
void main()
{
clrscr();
sumdig a;
a.input();
a.calculation();
a.output();
}

C++ Program to generate n number of Fibonacci series

C++ Program to generate n number of Fibonacci series

In mathematics, the Fibonacci numbers or Fibonacci series or Fibonacci sequence are the numbers in the following integer sequence:

1,1,2,3,5,8,13,21,34,55,89,144….

or (often, in modern usage):

0,1,1,2,3,5,8,13,21,34,55,89,144……(sequence A000045 in OEIS)

By definition, the first two numbers in the Fibonacci sequence are 1 and 1, or 0 and 1, depending on the chosen starting point of the sequence, and each subsequent number is the sum of the previous two.                                                wikipedia

#include<iostream.h>
class febin
{
int f,s,ne,n,i;
public:
void input()
{
cout<<"How many elements do you want in febinocci series\n";
cin>>n;
}
void calculation()
{
f=0;
s=1;
cout<<f<<" ";
for (i=1;i<n;i++)
{
ne=f+s;
cout<<ne<<" ";
s=f;
f=ne;
}
}
};
void main()
{
clrscr();
febin a;
a.input();
a.calculation();
}

C++ Program to check whether the number is palindrome or not

C++ Program to check whether the number is palindrome or not

A palindrome is a word, phrase, number, or other sequence of symbols or elements, whose meaning may be interpreted the same way in either forward or reverse direction.[1] Famous examples include "Amore, Roma", "A man, a plan, a canal: Panama" and "No 'x' in 'Nixon'". --- wiki

#include<iostream.h>
#include<conio.h>
class palindrome
{
int n1,n2,rem,rev;
public:
void input()
{
cout<<"Enter the number\n";
cin>>n1;
}
void calculation()
{
rev=0;
n2=n1;
while (n1>0)
{
rem=n1%10;
n1=n1/10;
rev=rev*10+rem;
}
}
void output()
{
if(n2==rev)
cout<<"Number is palindrome";
else
cout<<"Number is not palindrome";
}
};
void main()
{
clrscr();
palindrome a;
a.input();
a.calculation();
a.output();
getch();
}

C++ program to check whether the number is prime or not

C++ program to check whether the number is prime or not

#include<iostream.h>
#include<conio.h>
class prime
{
int num,i,p;
public:
void input()
{
cout<<"Enter any number\n";
cin>>num;
}
void output()
{
if(num==1 || num==2)
cout<<"Number is prime";
else
{
for(i=2;i<num;i++)
{
if(num%i==0)
 {
cout<<"Number is not prime";
break;
 }
 else
 p++;
 if(i==num-1)
 {
 if (p!=0)
 cout<<"Number is prime";
 }
 }
 }
}
};
void main()
{
clrscr();
prime a;
a.input();
a.output();
getch();
}

C++ Program to do operation on matrices

C++ Program to do operation on matrices

This is done in Code::Blocks Ide. Some modification are needed to run in Turbo C++ ide, like changing header into iostream.h, adding one more header conio.h and hence getch at the end of the program, removing using namespace std;, and all

#include<iostream>
#include<stdlib.h>
using namespace std;
class matrix
{
    int fraw,fcol,sraw,scol,i,j,k;
    int f[50][50],s[50][50],l[50][50];
public:
    void input()
    {
        cout<<"Enter number of raws and columns do you want for fisrt matrix\n";
cin>>fraw>>fcol;
cout<<"Enter number of raws(same as number of columns in first) and columns of second matrix\n";
cin>>sraw>>scol;
cout<<"Enter "<<fraw*fcol<<"elements of first matrix\n";
for(i=0;i<fraw;i++)
{
for(j=0;j<fcol;j++)
{
cin>>f[i][j];
}
}
cout<<"Enter "<<sraw*scol<<"elements of second matrix\n";
for(i=0;i<sraw;i++)
{
for(j=0;j<scol;j++)
{
cin>>s[i][j];
}
    }
    }
    void addition()
    {
        cout<<"Sum of two matrices\n";
for(i=0;i<fraw;i++)
{
for(j=0;j<fcol;j++)
{
l[i][j]=f[i][j]+s[i][j];
cout<<"\t"<<l[i][j];
}
cout<<"\n";
}
    }
void substraction()
{
    cout<<"Difference of two matrices\n";
for(i=0;i<fraw;i++)
{
for(j=0;j<fcol;j++)
{
l[i][j]=f[i][j]-s[i][j];
cout<<"\t"<<l[i][j];
}
cout<<"\n";
}
}
void multiplication()
{
    if(fcol!=sraw)
        cout<<"No of columns of First matrix and raws of second matrix is not same, multiplication is not allowed";
    else
    {
    for(i=0;i<fraw;i++)
for (j=0;j<scol;j++)
{
l[i][j]=0;
}
for(i=0;i<fraw;i++)
for (j=0;j<scol;j++)
for (k=0;k<fcol;k++)
{
l[i][j]=l[i][j]+f[i][k]*s[k][j];
}
for(i=0;i<fraw;i++)
{
for (j=0;j<scol;j++)
{
cout<<l[i][j]<<"\t";
}
cout<<"\n";
}
}
}
void read()
{
    cout<<"Elements of first matrix\n";
for(i=0;i<fraw;i++)
{
for(j=0;j<fcol;j++)
{
cout<<f[i][j]<<"\t";
}
cout<<"\n";
}
cout<<"Elements of second matrix\n";
for(i=0;i<sraw;i++)
{
for(j=0;j<scol;j++)
{
cout<<s[i][j]<<"\t";
}
cout<<"\n";
}
};
};
int main()
{
int c;
char an;
matrix a;
a.input();
do
{
    cout<<"Choose from the following options:\n";
    cout<<"1 Addition\t\t2 Subtraction\n";
    cout<<"3 Multiplication\t4 Reading\n";
    cout<<"5 Exit";
    cin>>c;
    switch (c)
    {
    case 1:
        a.addition();
        break;
    case 2:
        a.substraction();
        break;
    case 3:
        a.multiplication();
        break;
    case 4:
        a.read();
        break;
    default:
        exit(0);
    }
    cout<<"Do you want to continue: y/n";
    cin>>an;
}
while(an=='y'||an=='Y');
return 0;
}

C++ Program to demonstrate operator overloading

C++ Program to demonstrate operator overloading function (Unary Operator) Using friend function
#include<iostream>
class A
{
int x,y;
public:
void input ()
{
cout<<"Enter X and Y values\n";
cin>>x>>y;
}
void disp()
{
cout<<"x is "<<x<<endl<<"y= "<<y<<endl;
}
friend void operator --(A &o);
friend void operator ++(A &o);
};
void operator --(A &o)
{
o.x=--o.x;
o.y=--o.y;
}
void operator ++(A &o)
{
o.x++;
o.x=o.x;
o.y++;
o.y=o.y;
}
int main()
{
A a;
a.input();
a.disp();
cout<<"After decrimenting\n";
//accessing unary minus operator
--a;//calling operator -()
a.disp();
++a;
cout<<"After incrimenting\n";
a.disp();
return 0;
}